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8604 Posts Member #: 573 Formerly Axel Podland |
22nd Oct, 2010 at 07:02:50pm
Here's something to think about.
Edited by Paul S on 25th Oct, 2010. Saul Bellow - "A great deal of intelligence can be invested in ignorance when the need for illusion is deep."
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Forum Mod 10980 Posts Member #: 17 ***16*** SouthPark, Colorado |
22nd Oct, 2010 at 07:05:09pm
Chewing.... But it tastes salty. Will report back later. On 17th Nov, 2014 Tom Fenton said:
Sorry to say My Herpes are no better Ready to feel Ancient ??? This is 26 years old as of 2022 https://youtu.be/YQQokcoOzeY |
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![]() 1745 Posts Member #: 375 Post Whore Leicestershire |
22nd Oct, 2010 at 07:16:36pm
Tastes like chicken |
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5988 Posts Member #: 2024 Formally Retired Rural Suffolk |
22nd Oct, 2010 at 07:38:24pm
On 22nd Oct, 2010 Paul S said:
The second is the velocity energy or kinetic energy. The E=mc2 bit. On 22nd Oct, 2010 Paul S said:
Chew on that :) I nearly choked
Whilst your original equation is true (so far as I can remember), E=mc^2 is nuclear physics, "m" being the difference in mass between atoms before/after a fission or fusion event in that equation. You're thinking of e=1/2 mv^2 which is a completey different "m"
Schrödinger's cat - so which one am I ??? |
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8604 Posts Member #: 573 Formerly Axel Podland |
22nd Oct, 2010 at 07:48:51pm
Rod, you are correct. Just testing :)
Saul Bellow - "A great deal of intelligence can be invested in ignorance when the need for illusion is deep."
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![]() 1497 Posts Member #: 100 Parisien Turbo Expert Paris\' suburb |
22nd Oct, 2010 at 09:36:14pm
monkeying |
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8604 Posts Member #: 573 Formerly Axel Podland |
23rd Oct, 2010 at 03:26:33pm
On 22nd Oct, 2010 fab said:
monkeying I think that loosely translates to "ridiculous"
I've just done some calculations and the numbers are so significant that I can hardly believe them. Rather than make a fool of myself, anyone care to check my calcs by PM? Saul Bellow - "A great deal of intelligence can be invested in ignorance when the need for illusion is deep."
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![]() 1497 Posts Member #: 100 Parisien Turbo Expert Paris\' suburb |
23rd Oct, 2010 at 07:45:49pm
Monkeing is abit like aping, a lot more amicaly.
On 23rd Oct, 2010 Paul S said:
On 22nd Oct, 2010 fab said:
monkeying I think that loosely translates to "ridiculous"
I've just done some calculations and the numbers are so significant that I can hardly believe them. Rather than make a fool of myself, anyone care to check my calcs by PM? |
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8604 Posts Member #: 573 Formerly Axel Podland |
24th Oct, 2010 at 10:45:19am
On 23rd Oct, 2010 fab said:
you 've just lighted why the inlet valve need to close later than bdc, their's still energy left in them from their acceleration created by the earlier vaccumed cylinder. Fab, this is about how you measure boost. It is independant of mass flow - there is no "m" value in the above equation, although I did confuse the issue. The inertia that fills the cylinder after BDC is due to inertia derived from mv2/2 which does take account of the mass flow in the port. If you do a dimensional analysis of the equation ^^^ you get N/m2 for all three components, so i'm happy with the derivation of the original Bernouli formula which is far more complex. The big problem is what port velocity to use as this varies from zero to near 200 m/s at peak. I'm taking 2.8cm as the port diameter, as this is the diameter of the MG Metro manifold port at the vacuum/boost take off. At peak port velocity, on a 1293 at 7000rpm, then the actual boost at a measured boost of 15 psi could be as high as 22 psi! Reality check is that the average increase over the whole engine cycle is around 1 psi, but it depends how the boost gauge handles the pulses. Saul Bellow - "A great deal of intelligence can be invested in ignorance when the need for illusion is deep."
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8215 Posts Member #: 90 Post Whore Somewhere around Swindon |
24th Oct, 2010 at 10:53:45am
i did my own energy equation
Crystal Sound Audio said:
Why wolfie...you should have your name as Fuckfaceshithead ! "A common mistake that people make when trying to design something completely foolproof is to underestimate the ingenuity of complete fools."-Douglas Adams |
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Forum Mod ![]() 1322 Posts Member #: 28 Post Whore Milton Keynes |
24th Oct, 2010 at 07:06:58pm
I'm just pondering this from first principals, infact now I think about it am I even talking about the same thing? Anway here goes:
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8604 Posts Member #: 573 Formerly Axel Podland |
24th Oct, 2010 at 07:17:35pm
No, this is simply the dynamics of the changing state of the internal energy of the inlet charge. Saul Bellow - "A great deal of intelligence can be invested in ignorance when the need for illusion is deep."
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388 Posts Member #: 442 Senior Member Manchester |
24th Oct, 2010 at 09:09:54pm
Suppose temperature of inlet charge will have an effect on this? |
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5988 Posts Member #: 2024 Formally Retired Rural Suffolk |
24th Oct, 2010 at 09:31:51pm
Everything come back down to the universal gas equation,
Schrödinger's cat - so which one am I ??? |
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Forum Mod ![]() 5933 Posts Member #: 784 9 times Avon Park Class C winner Milton Keynes |
24th Oct, 2010 at 10:08:36pm
What the fuck are you talking about? You lost me I seriously doubt it! |
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8604 Posts Member #: 573 Formerly Axel Podland |
24th Oct, 2010 at 10:08:40pm
On 24th Oct, 2010 mcalvert39 said:
Suppose temperature of inlet charge will have an effect on this? Yes, temperature affects the air density. I've used the density of air at 35 Deg C. The point of trying to understand this is that it may explain the very high apparent VE figures needed to explain the high power outputs from relatively moderate boost levels. It may also explain why indicated boost pressures appear to drop as the revs rise. Saul Bellow - "A great deal of intelligence can be invested in ignorance when the need for illusion is deep."
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![]() 1497 Posts Member #: 100 Parisien Turbo Expert Paris\' suburb |
25th Oct, 2010 at 04:16:43am
good luck to explain these very high ve.. and i will stop there on this subject.
On 24th Oct, 2010 Paul S said:
On 24th Oct, 2010 mcalvert39 said:
Suppose temperature of inlet charge will have an effect on this? Yes, temperature affects the air density. I've used the density of air at 35 Deg C. The point of trying to understand this is that it may explain the very high apparent VE figures needed to explain the high power outputs from relatively moderate boost levels. It may also explain why indicated boost pressures appear to drop as the revs rise. |
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![]() 1497 Posts Member #: 100 Parisien Turbo Expert Paris\' suburb |
25th Oct, 2010 at 04:29:05am
If it can help Tdave mesured these years ago:
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8604 Posts Member #: 573 Formerly Axel Podland |
25th Oct, 2010 at 10:12:58am
On 25th Oct, 2010 fab said:
If it can help Tdave mesured these years ago: restrictor is flowing 120cfm, mety manifold 90cfm. They are just points on a square law curve and meaningless without the associated pressure drop. I'm sure TD would have used 25" water and atmospheic at the inlet. Put boost into the equation and consider it in terms of velocity and mass flow, then you gan get more than enough air flow for 200hp. Saul Bellow - "A great deal of intelligence can be invested in ignorance when the need for illusion is deep."
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8604 Posts Member #: 573 Formerly Axel Podland |
25th Oct, 2010 at 10:16:38am
On 25th Oct, 2010 fab said:
the pressure drop as rev rise is achieved by the restrictor. these boost pressure are mesured :after carb restrictor, and when you restrict an air flow it'll loose pressure cqfd, Mesure pressure drop thru the turbo carb/restrictor, then you'll know why I'm competely suspiscious about the mesured numbers. There is a pressure drop through the carb and restrictor, but what I'm talking about is how the pressure is measured after that. The same principles apply to aircraft wings. if you measure the pressure on the top and bottom of an aircraft wing in flight, you get a big difference due to the velocity difference. It's this that lifts the plane of the ground. Nothing to do with pressure loss, inertia or pulses. Saul Bellow - "A great deal of intelligence can be invested in ignorance when the need for illusion is deep."
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2496 Posts Member #: 1954 Post Whore Luton Bedfordshire |
25th Oct, 2010 at 12:58:04pm
So what about the heat? The kinetic energy may very well convert to pressure energy but where you affect one you affect another for the temperature to remain the same whit a decrease in velocity and incread in pressure does not the density have to change or are you suggesting a perfect trade off with pressure and velocity? Own the day
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8604 Posts Member #: 573 Formerly Axel Podland |
25th Oct, 2010 at 01:20:42pm
Saul Bellow - "A great deal of intelligence can be invested in ignorance when the need for illusion is deep."
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![]() 1497 Posts Member #: 100 Parisien Turbo Expert Paris\' suburb |
25th Oct, 2010 at 02:19:48pm
Would you agree if i'm using a bit of the brandnew scotch band now???
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![]() 453 Posts Member #: 6449 Senior Member Brisbane, Australia |
25th Oct, 2010 at 02:38:05pm
They tried to teach me that at uni. So i dropped out.
In boost we trust |
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Forum Mod 10980 Posts Member #: 17 ***16*** SouthPark, Colorado |
25th Oct, 2010 at 03:59:37pm
The very fact that woodsie was getting well over 200hp eight years ago, using the restrictor, and a T3 turbo, (don't know what he's up to now though) should point that it's a whole different game with boost.
On 25th Oct, 2010 Paul S said:
On 25th Oct, 2010 fab said:
If it can help Tdave mesured these years ago: restrictor is flowing 120cfm, mety manifold 90cfm. They are just points on a square law curve and meaningless without the associated pressure drop. I'm sure TD would have used 25" water and atmospheic at the inlet. Put boost into the equation and consider it in terms of velocity and mass flow, then you gan get more than enough air flow for 200hp. On 17th Nov, 2014 Tom Fenton said:
Sorry to say My Herpes are no better Ready to feel Ancient ??? This is 26 years old as of 2022 https://youtu.be/YQQokcoOzeY |
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Andy
